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Monochromatic light of frequency 6.0 xx 10^(14) Hz is produced by a laser. The power emitted is 2 xx 10^(-3) W. The number of photons emitted, on the average, by the source per second is |
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Answer» Solution : POWER = NHV where n = NUMBER of photons per second `=2.0xx10^(-3)=nxx6.6xx10^(-34)xx6xx10^14` `n=(2.0xx10^(-3))/(6.6xx10^(-34)xx6xx10^14)` `=(2.0xx10^(-3))/(39.6xx10^(-20))` = 5 x 10 photons per second |
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