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Monochromatic light of frequency6.0 x 1014 Hz is produced by alaser. The power emitted is2.0 x 10 W. Estimate the numberof photons emitted per second onan average by the source. |
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Answer» energy of one photon is = h* freq power is the energy per unit time therfore the energy given per second is 2 * 10^3 number of photons * energy of one photon = total energy number of photons = (2*10^3)/(6.636*10^-34 * 6 * 10^14) approxi mately = 5 * 10^23 photons . |
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