1.

Monochromatic light of requency 6.0xx10^(14) Hz is produced by a laser. The power emitted is 2.0xx10^(-3)W. Calculate the (i) energy of a photon in the light beam, and (ii) number of photons emitted on an average by the source.

Answer»

Solution :Here FREQUENCY `v=6.0xx10^(14)Hz` and power of laser `P=2.0xx10^(-3)W`
(i) Energy of a photon `E=hv=6.63xx10^(-34)xx6.0xx10^(14)=3.978xx10^(-19)J=3.98xx10^(-19)J`
(ii) Number of photons emitted PER second by laser source
`n=(P)/(E)=(2.0xx10^(-3))/(3.98xx10^(-19))=5.03xx10^(15)s^(-1)`.


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