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Monochromatic light of wavelength 589 nm is incident from air on a water surface. If refractive index for water is 1.33, find the wavelength, frequency and speed of the refracted light. |
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Answer» Solution :Here wavelength of incident light in air `lambda = 589 nm = 589 xx 10^(-9)` m, and speed of light in air `c = 3 xx 10^(8) ms^(-1)` `therefore` FREQUENCY of light `v=c/lambda = (3 xx 10^(8))/(589 xx 10^(-9)) = 5.09 xx 10^(14) Hz` `therefore` REFRACTIVE INDEX of water n=1.33 `therefore` Wavelength of REFRACTED light `v. = v = 5.09 xx 10^(14)` Hz and speed of refracted light `v=c/n =(3 xx 10^(8))/1.33 = 2.26 xx 10^(8) ms^(-1)` |
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