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Monochromatic light of wavelength 632.8 nm is produced by a helium-neon laser. The power emitted is 9.42mW. Find the energy and momentum of each photon in the light beam, |
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Answer» <P> Solution :Here, `lamda=632.8nm=632.8xx10^(-9)m`,`P=9.42mW=9.42xx10^(-3)W` Energy of each photon in the light beam is `E=(hc)/(lamda)=(6.62xx10^(-34)xx3xx10^(8))/(632.8xx10^(-9))=3.14xx10^(-19J)` Momentum of each photon in the light beam is `P=(H)/(lamda)=(6.62xx10^(-34))/(632.8xx10^(-9))1.05xx10^(-27)KGMS^(-1)` |
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