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Monochromatic light of wavelength 632.8 nm is produced by a helium-neon laser. The power emitted is 9.42mW. How fast does a hydrogen atom have to travel in order to have to have the same momentum as that of the photon ? |
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Answer» Solution :Here, `lamda=632.8nm=632.8xx10^(-9)m`, `P=9.42mW=9.42xx10^(-3)W` Momentum of a HYDROGEN ATOM is EQUAL to the momentum of a photon. Therefore, required speed (v) of the hydrogen atom is `v=("Momentum of photon ")/(m_(H))=(1.05xx10^(-27))/(1.66xx10^(-27))=0.63ms^(-1)` |
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