Saved Bookmarks
| 1. |
Monochromatic light waves of intensitiesI_(1) and I_(2), and a constant phase difference phi produce an interference pattern. State an expression for the resultant intensity at a point in thepattern. Hence deduce the expressions for the resultant intensity, maximum intensity and minimum intensity if I_(1)=I_(2)=I_(0). |
|
Answer» Solution :Consider a two-source interference PATTERN produced by monochromatic light waves of intensities `I_(1) and I_(2),` and a constant PHASE difference `phi`. The resultant intensity at a point in the pattern is `I=I_(1)+I_(2)+2 sqrt(I_(1)*I_(2))*cos phi ""` ...(1) If`I_(1)=I_(2)=I_(0),` `I=I_(0)+I_(0)+ 2 sqrt(I_(0) * I_(0))* cos phi ` `=2I_(0)(1+cos phi) "" ` ...(2) At a point of constructive interference with maximum intensity, `cos phi =1` and `I_(max) =2I_(0)(1+1)=4I_(0) "" `...(3) At a point of destructive interference with minimum intensity,`cos phi = -1` and `I_(min) =2I_(0) (1-1)=0 ""`...(4) |
|