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MULTI CHOICE:22. Choose the correct statement[H 42, 1 Joule = 107 ergs; 1 Kilowatt hour= 36x101; 1 electron volt (eV) = 1.6x10""J]1) Amount of heat required to melt 45 gm of ice is 4.2 watt hours.lint: Various units of energy and their relation 1cal -2) 1 joule =watt hours36003) Amount of heat required to melt 45 gm of ice is 15120 J4) 1 joule = watt hours4600

Answer»

Ans. 21kwh=36×10^5 jouleSo, 1joule=1×10^3÷36×10^5 वॉट hour => 1 जूल =1/36×10^2

2 is correction because 1 Joule =1\36*10^2



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