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Multiply 00100110 by 10011110 in GF(2^8) with modulus 100011011.The result is(a) 00101111(b) 00101100(c) 01110011(d) 11101111I have been asked this question during an interview.This interesting question is from Polynomial and Modular Arithmetic- III in section Basic Concepts in Number Theory and Finite Fields of Cryptograph & Network Security

Answer» CORRECT option is (a) 00101111

To explain I would SAY: On performing POLYNOMIAL MULTIPLICATION with respect to modulus 100011011 we GET 00101111.


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