1.

MX_(2) dissociates into M^(2+) and X^(-) ions in an aqueous solution, with a degree of dissociation (alpha) of 0.5. The ratio of solution to the value of depression of freezing point in the absence of ionic dissociation is

Answer»


Solution :`MX_(2)HARR M^(2+)+2X^(-)`
`m_(0)(1-alpha) "" m_(0)alpha "" 2m_(0)alpha , m=m_(0)(1+2alpha)`
`therefore m=m_(0)(1+2xx0.5)=2m_(0)` (as given)
`((-Delta T_(f))_("OBSERVED"))/((-Delta T_(f))_("undissociated"))=i=(m)/(m_(0))=2`


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