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My answer should be like this( as I send a pic) and ur questin is how much of heat energy is required when 20grams of ice at 0°c to convert water vapour at 100°c ??if u say correct i will send u 200 pointsif ur like icant idont know i will report that |
| Answer» 2000 cal , 8360 J.mass of water = 20 gmChange in TEMPERATURE = 100-0 = 100Heat energy required = mass of water (gm)× Change in temperature (°C) cal.heat = mass * change in temperaure= 20 × 100 = 2000 cal1 Joule= 4.18 * 1cal=2000 × 4.18 = 8360 JExplanation:PLZZ MARK ME AS BRAINLIEST ANSWER AND SEND 200 POINTS AS U SAID | |