1.

n_1 and n_2 are refractive indices of core and cladding of optical fibre respectively, then maximum acceptance angle theta = ......

Answer»

`SIN^(-1)((n_2)/(n_1))`
`sin^(-1)SQRT(n_1^2-n_2^2)`
`[TAN^(-1)(n_2)/(n_1)]`
`[tan^(-1)(n_1)/(n_2)]`

SOLUTION :`sin^(-1)sqrt(n_1^2-n_2^2)`


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