1.

`N_2` accept electron and convert into `N_2^-`, where this electron goesA. Antibonding `pi` molecules orbitalsB. Bonding `pi` molecular orbitalC. `sigma` bonding molecular orbitalsD. `sigma`-anti-bonding molecular orbital

Answer» Correct Answer - A
`N_2` molecule has 14 electrons. The molecular orbitals electronic configuration of the molecule is as
`N_2: K K (simga2s)^(2),(sigma^(**)2s)^(2),(pi2p_(x))^(2),(pi 2p_(y))^(2)~~(sigma2p_(z))^(2)`
`N_(2)^(-)` ions is formed when `N_(2)` accept an electron hence, it has 15 electrons. the molecular orbital electronic cofiguration of the molecule is as :
`N_(2)^(-) : K K (sigma2s)^(2),(sigma^(**)2s)^(2)~~(pi 2p_(x))^(2),(pi 2p_(y))^(2),(sigma2p_(z))^(2),(pi^(**)2p_(x))^(1)`
Hence, this electrons goes to antibonding `pi` molecular orbital.


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