InterviewSolution
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InterviewSolution
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`N_(2)O_(4)(g)` is dissociated to an extent of `20%` at equilibrium pressure of `1.0` atm and `57^(@)C`. Find the percentage of `N_(2)O_(4)` at `0.2` atm and `57^(@)C`. |
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Answer» Correct Answer - A::D `{:(,N_(2)O_(4)(g), hArr,2NO_(2)(g)),(underset(("moles"))(t=0),a,,0),(t=t_("eq"),3-aalpha,,2aalpha):}` `K_(p)=(P_(NO_(2))^(2))/(P_(N_(2)O_(4)))=(((2aalpha)/(a+aalpha).P)^(2))/((a-aalpha)/(a+aalpha)P)=(4alpha^(2)P)/(1-alpha^(2))` `K_(p)` will remain same as is constant `rArr (4alpha_(1)^(2)P_(1))/(1-alpha_(1)^(2))=(4alpha_(2)^(2)P_(2))/(1-alpha_(1)^(2))` `[alpha_(1)=0.2, P_(1)=1.0 "atm" P_(2)=0.2 "atm"]` `rArr alpha_(2)=0.41` |
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