1.

`N_(2)O_(4)` is dissociated to `33%` and `50%` at total pressure `P_(1)` and `P_(2)atm` respectively. The ratio of `P_(1)//P_(2)` is:A. `7//4`B. `7//3`C. `8//3`D. `8//5`

Answer» `underset(1-alpha)underset(2)(N_(2)O_(4))hArrunderset(2alpha)underset(0)(2NO_(2))`
`K_(p)=((n_(NO_(2)))^(2))/((n_(N_(2)O_(4))))xx[(P)/(sumn)]^(1)`
For `33%` dissociation:
`K_(p)=((2xx33)^(2))/(67)xx[(P_(1))/(133)]^(1)`
For `50%` dissociation:
`K_(p)=((2xx50)^(2))/(50)xx[(P_(2))/(150)]^(1)`
`:. (P_(1))/(P_(2))=(133xx67xx(2xx50)^(2))/((2xx33)^(2)xx150xx50)=2.72`


Discussion

No Comment Found

Related InterviewSolutions