n-butane is produced by the monobromination of ethane followed by Wurtz reaction. Calculate the volume of ethane at NTP required to produce 55g of n-butane, if the bromination takes place with 90% and the Wurtz reaction with 85% yield.

n-butane is produced by the monobromination of ethane followed by Wurt

1.	n-butane is produced by the monobromination of ethane followed by Wurtz reaction. Calculate the volume of ethane at NTP required to produce 55g of n-butane, if the bromination takes place with 90% and the Wurtz reaction with 85% yield.
Answer» Solution :`C_(2)H_(6) rarr C_(2)H_(5)Br` `2C_(2)H_(5)Br + 2NA underset("reaction")overset("Wurtz")rarr C_(4)H_(10)+ 2NaBr` 1 mole of `C_(2)H_(6)` gives 1 mole of `C_(2)H_(5)Br` and 2 moles of `C_(2)H_(5)Br` give 1 mole of `C_(4)H_(10)`.Let the number of moles of `C_(2)H_(6)` be N `therefore` n moles of `C_(2)H_(6)` will give 0.9n moles of `C_(2)H_(5)Br` (90%) and 0.9n moles of `C_(2)H_(5)Br` will give `(0.45 n xx 0.85)` moles of n-butane (85%). Thus, `0.45n xx 0.85= (55)/(58) (C_(4)H_(10)=58)` n= 2.789 moles `therefore` volume of `C_(4)H_(10)` at NTP= `2.789 xx 22.4` =55.53 litres