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N(E) = 40 , n(A) = 23 , n(B') = 28 Find n(A U ) |
Answer» N(U)= 60N(U)= 60N(AUB)'=10N(U)= 60N(AUB)'=10N(AUB)=N(U)- N(AUB)'N(U)= 60N(AUB)'=10N(AUB)=N(U)- N(AUB)'= 60-10N(U)= 60N(AUB)'=10N(AUB)=N(U)- N(AUB)'= 60-10=50N(U)= 60N(AUB)'=10N(AUB)=N(U)- N(AUB)'= 60-10=50So N(A INTERSECTION B)= N(A)+N(B) - N (AUB)N(U)= 60N(AUB)'=10N(AUB)=N(U)- N(AUB)'= 60-10=50So N(A intersection B)= N(A)+N(B) - N (AUB)= 35+24-50N(U)= 60N(AUB)'=10N(AUB)=N(U)- N(AUB)'= 60-10=50So N(A intersection B)= N(A)+N(B) - N (AUB)= 35+24-50=9......hope it will HELP you mam!!! |
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