1.

n identical bulbs operating on same voltage are available. When all such bulbs are connected in series to the same operating voltage source, then power consumed in each bulb = ...... W.

Answer»

nP
P
`(P)/(n)`
`(P)/(n^(2))`

Solution :`(P)/(n)`
The resistance of every BULB R= `(V^(2))/(P)`
The total resistance joined in SERIES of n bulb
R.= nR = `(nV^(2))/(P)`
`therefore `Total Power P. = `(V^(2))/(R.)= (V^(2) XX P)/(nV^(2)) = (P)/(n)`


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