1.

n identical cells each of emf epsilon and lnternal resistance r are connected in parallel with resistor R. The current nowing through resistor R is ..........

Answer»

`(n epsilon)/(R + NR)`
`(n epsilon)/(n R + r) `
`(epsilon)/(R + r)`
`(epsilon)/(nR + r)`

Solution :`(n epsilon)/(n R + r) `
TOTAL resistance of circuit = R + `(r)/(n) `
CURRENT I = `(epsilon)/(R + (r)/(n)) = (n epsilon)/(nR + r)`


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