1.

n object of mass 3 kg is at rest. A force vec(F)=6hat(i)t^(2) + 4hat(j)tis applied, then velocity of the object at t = 3 second is :

Answer»

`18hat(i) + 3hat(j)`
`18hat(i)+6hat(j)`
`3hat(i)+18hat(j)`
`18hat(i)+4hat(j)`

Solution :`m=(DV)/(dt)=6hatit^(2) + hatjt,`But m=3kg
`dv=6/3hati t^(2)dt + 4/3 hatjt dt`
`v=2hati[t^(3)/3]_(0)^(3) + 4/3hatj[t^(2)/2]_(3)^(0)`
`2hati xx27/3 + 4/3 hatj xx 9/2 = 18hati + 6hatj`


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