1.

n-propyl bromide on treating with alcoholic KOH produces

Answer»

PROPYNE
Propanol
Propane
Propene

Solution :`underset"Propylbromide"(CH_3CH_2CH_2Br)+underset"(alc.)"(KOH)to underset"propene"(CH_3CH)=CH_2+KBr+H_2O`
This reaction REMOVES a molecule of HX and therefore, the reaction is called dehydrohalogenation. The hydrogen atom is ELIMINATED from `beta`-carbon atom (carbon atom next to the carbon to which halogen is ATTACHED). Therefore the reaction is ALSO called `beta`-elimination reaction


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