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n resistances, each of r Ω, when connected in parallel give an equivalent resistance of R Ω. If these resistances were connected in series, the combination would have a resistance in horns equal to(a) n2 R(b) \(\frac{R}{n^2}\)(c)\(\frac{R}{n}\)(d) nR |
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Answer» Correct answer is (a) n2 R Resistance in parallel combination, R = \(\frac{r}{n}\) ⇒ r = Rn Resistance in series combination, R’ = nr = n2R |
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