n resistances, each of r Omega, when connected in parallel give an equivalent resistance of R Omega. If these resistances were connected in series, the combination would have a resistance in homs equal to

n resistances, each of r Omega, when connected in parallel give an equ

1.	n resistances, each of r Omega, when connected in parallel give an equivalent resistance of R Omega. If these resistances were connected in series, the combination would have a resistance in homs equal to
Answer» `n^(2)R` `(R )/(n^(2))` `(R )/(n)` NR SOLUTION :Resistance in PARALLEL combination, `R=(r )/(n) RARR r=Rn` Resistance in SERIES combination, `R.=nr=n^(2)R`

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n resistances, each of r Omega, when connected in parallel give an equivalent resistance of R Omega. If these resistances were connected in series, the combination would have a resistance in homs equal to

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