1.

n resistors each of resistance r are connected to a battery of emf epsilonand internal resistance r. Then the ratio of terminal voltage to emf of battery = ...... .

Answer»

N
`(n)/(n + 1)`
`(1)/(n+ 1)`
`(n+ 1)/(n)`

Solution :`(n)/(n+ 1) `
`epsilon = I XX ` total RESISTANCE of circuit

`epsilon = I xx (n + 1) r "" `...... (1) and
V= I (r + r + r + ... N TIMES)
V = Inr...... (2)
`therefore (V)/(epsilon) = (n)/(n+ 1)`


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