1.

NaCl + K_(2)Cr_(2)O_(7)+H_(2)SO_(4) rarr NA_(2)SO_(4) + K_(2) SO_(4) +H_(2)O +X The oxidation state chromium in the product X

Answer»

`+5`
`+6`
`+7`
`+8`

Solution :`4NaCl + K_(2) Cr_(2) O_(7) + 3H_(2) SO_(4) rarr 2Na_(2) SO_(4)+K_(2)SO_(4) + 3H_(2)O + 2CrO_(2) Cl_(2)`
THUS X is `CrO_(2) Cl_(2)` chromyl chloride
`:. ` O.N. of Cr is ` +6`


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