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Nalorphene (C_19H_21NO_3) , similar to morphine, is used to combat withdrawal symptoms innarcotic users. Dose of nalorphene generally given is 1.5 mg. Calculate the mass of 15 xx 10^(-3) maqueous solution required for the above dose. |
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Answer» Solution :`1.5 xx 10^(-3)`m solution MEANS `1.5 xx 10^(-3)` mole of nalorphene is dissolved in 1 kg of WATER. Molar mass of `C_19H_21NO_3 = 19 xx 12 + 21 + 14 + 48 = 311 g "mol"^(-1)` ` therefore1.5 xx 10^(-3) `mole of `C_19H_21NO_3` contains ` = 1.5 xx 10^(-3) xx 311 g = 0.467g = 467 mg` of ` C_19H_21NO_3` Mass of solution = 1000 g + 0.467 g = 1000.467 g For 467 mg of nalorphene, solution REQUIRED = 1000.467 g For 1.5 mg of nalorphene, solution required =`(1000.467)/(467) xx 1.5 = 3.21 g ` |
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