1.

Name the alkene formed when ethyl bromide is heated with alcoholic KOH.

Answer»


Solution :In this reaction two ATOMS are LOST from reactant ethyl bromide to form carbon-carbon double BOND. This is an elemination reaction and product FORMED as ethene `(CH_(2) = CH_(2))`
`H-underset(H)underset(|)overset(H)overset(|)(C)-underset(Br)underset(|)overset(H)overset(|)(C)-H underset(DELTA)overset("Alc. KOH")to H-underset("Ethene")(overset(H)overset(|)(C))-H+KBr+H_(2)O`


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