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Name the experiment which confirms the existence of wave nature of electrons. Derive the expression for de-Broglie wavelength of an electron moving under a potential difference of V volts, (ii) An electron and a proton have the same Kinetic Energy, Which of these particles has the shorter de-Broglie wavelength? |
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Answer» <P> Solution : Davisson-Germer experiment An electron of charge e, mass m accelerated through a potential difference of v VOLTS, Kinetic energy equals the WORK done (eV) on it by the electric FIELD:K=eV `K=p^(2)/(2m'), p=sqrt((2mk))` (ii) `p=sqrt((2meV))` the de-Broglie wavelength 1 of the ELECTRONS is: `lambda=h/p`. For same `KE, lambda alpha 1/sqrtm` (iii) For same KE, l a........ As mass of proton is greater than that of electron `therefore lambda_(p), lambda_(a)`. |
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