InterviewSolution
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InterviewSolution
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Name the gas that can readily decolourise acidified `KMnO_(4)` solution:A. `CO_(2)`B. `SO_(2)`C. `NO_(2)`D. `P_(2)O_(5)` |
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Answer» Correct Answer - B `SO_(2)` gas can readily oxidise acidified `KMnO_(4)` solution because `KMnO_(4)` is an oxidising agent and `SO_(2)` act as reducing agent. `2MnO_(4)^(-) + 5SO_(2) +2H_(2)O to 2Mn^(2+) + 5SO_(4)^(2-) + 4H^(+)` While other options such as `NO_(2)` (strong oxidising agent), `CO_(2)` (neither oxidising agent nor reducing agent) cannot decolourise acidified `KMnO_(4)` solution. |
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