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Name the members of the lanthanoid series which exhibit +4 oxidation states and those which exhibit +2 oxidation states. Try to correlate this type of behaviour with the electronic configuration of these elements. |
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Answer» Solution :` +4 = ""_(58)Ce, ""_(59)Pr, ""_(60)ND, ""_(65)Tb, ""_(66)Dy` `+2 = ""_(60)Nd, ""_(62)Sm, ""_(63)Eu, ""_(69)Tm, ""_(70)Yb` +2 OXIDATION state is exhibited when the LANTHANOID has the configuration `5d^06s^2` so that 2 electrons are easily lost. +4 oxidationstate is exhibited when the configuration left is CLOSE to `4f^(0) (e.g, 4f^0 , 4f^1, 4f^2) ` or close to `4f^7 (e.g. 4f^7 or 4f^8)` |
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