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| 1. |
NaOH behaves as a base while Zn(OH)_(2) is amphoteric why? |
| Answer» Solution :In NaOH the bond electronegativity difference between NA and oxygen is greater than between Hand O and therefore it is the Na-O bond that breaks RELEASING OH. But in case of Zn-O-H bond the difference of electronegativity of ZnO and O-H are almost same. So there is equal PROBABILITY that the bond breaks in both ways LEADING to an amphoteric behaviour | |