^nC0 = ________________(a) n!(b) 1(c) \(\frac{1}{(n)!}\)(d) (n-1)!I got this question in a national level competition.I want to ask this question from Combinations in section Permutations and Combinations of Mathematics – Class 11

^nC0 = ________________(a) n!(b) 1(c) \(\frac{1}{(n)!}\)(d) (n-1)!I go

1.	^nC0 = ________________(a) n!(b) 1(c) \(\frac{1}{(n)!}\)(d) (n-1)!I got this question in a national level competition.I want to ask this question from Combinations in section Permutations and Combinations of Mathematics – Class 11
Answer» Correct choice is (b) 1 The explanation: We KNOW, ^nCr = \(\FRAC{n!}{(n-R)! r!}\). ^nC0 = \(\frac{n!}{(n-0)! 0!} = \frac{n!}{n!(1)}\) = 1.

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^nC0 = ________________(a) n!(b) 1(c) \(\frac{1}{(n)!}\)(d) (n-1)!I got this question in a national level competition.I want to ask this question from Combinations in section Permutations and Combinations of Mathematics – Class 11

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