^nCn = ________________(a) n!(b) 1(c) \(\frac{1}{(n)!}\)(d) (n-1)!The question was asked by my school teacher while I was bunking the class.This interesting question is from Combinations in section Permutations and Combinations of Mathematics – Class 11

^nCn = ________________(a) n!(b) 1(c) \(\frac{1}{(n)!}\)(d) (n-1)!The

1.	^nCn = ________________(a) n!(b) 1(c) \(\frac{1}{(n)!}\)(d) (n-1)!The question was asked by my school teacher while I was bunking the class.This interesting question is from Combinations in section Permutations and Combinations of Mathematics – Class 11
Answer» Correct answer is (b) 1 The best I can EXPLAIN: We know, ^NCR = \(\frac{n!}{(n-R)! r!}\). ^nCn = \(\frac{n!}{(n-n)! n!} = \frac{n!}{(0)! n!}\) = 1/1 = 1.

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^nCn = ________________(a) n!(b) 1(c) \(\frac{1}{(n)!}\)(d) (n-1)!The question was asked by my school teacher while I was bunking the class.This interesting question is from Combinations in section Permutations and Combinations of Mathematics – Class 11

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