^nCr = ________________(a) n!(b) \(\frac{n!}{r!}\)(c) \(\frac{n!}{(n-r)!}\)(d) \(\frac{n!}{(n-r)! r!}\)This question was addressed to me during an online exam.This intriguing question comes from Combinations in chapter Permutations and Combinations of Mathematics – Class 11

^nCr = ________________(a) n!(b) \(\frac{n!}{r!}\)(c) \(\frac{n!}{(n-r

1.	^nCr = ________________(a) n!(b) \(\frac{n!}{r!}\)(c) \(\frac{n!}{(n-r)!}\)(d) \(\frac{n!}{(n-r)! r!}\)This question was addressed to me during an online exam.This intriguing question comes from Combinations in chapter Permutations and Combinations of Mathematics – Class 11
Answer» Correct answer is (d) \(\FRAC{n!}{(n-R)! r!}\) The best I can explain: Permutation is known as SELECTION. ^NCR means arranging r OBJECTS out of n. ^nCr = \(\frac{n!}{(n-r)! r!}\).

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