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Negation of the statement p → (q ∧ r) is1. ~ p → ~ (q ∧r)2. ~ p ∨(q ∧r)3. (q ∧r) → p4. p ∧(~ q ∨ ~ r) |
Answer» Correct Answer - Option 4 : p ∧(~ q ∨ ~ r) p ∧(~ (q ∧r)) = p ∧(~ q ∨~ r) |
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