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| 1. |
Neglecting the liquid junction potential, calculate the emf of the following cell at 25^@C H_2 (1atm) |0.5 M HCOOH||1M CH_3 COOH|H_2(1atm) The dissociation constants of HCOOH and CH_3COOH are 1.77 times 10^-4 and 1.8 times 10^-8 respectively. |
| Answer» SOLUTION :`-0.0246` VOLT | |