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Neon -23 decays in the following way ""_(10)^(23)Nerarr""_(11)^(23)Ne+""_(-1)e^0+barv. Find the minimum and maximum kinetic energy that the beta particle (""_(-1)e^(0)) can have . The atomic masses of ""^(23)Ne and ""^(23)Naare 22.9945u and 22.9898 u, respectively. |
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Answer» SOLUTION :Here, atomic masses are given (not the NUCLEAR masses ), but still We can beuse them for Calculating the mass defect because mass of electrons get cancelled both sides. THUS, Mass defect `Deltam = (22.9945-22.9898) = 0.0047u` `:. Q = (0.0047u) (931.5 MeV//u) = 4.4 MeV` Hence, the energy of beta poetical can range from 0.to 4.4 Me V. |
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