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Net capacitance of three identical capacitors in series is 1 muF. What will be their net capacitance if connected in parallel ? Find the ratio of energy stored in the two configurations if they are both connected to the same source. |
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Answer» Solution :It is given that `C_1 = C_2 =C_3 =C` (SAY) Then their equivalent capacitance in series `C_s = C/3 =1 MU F` `rArr C = 3muF` `:.` Net capacitance in parallel arrangement `C_p = 3C = 3 xx 3 muF = 9 muF` Let the capacitor combination be CONNECTED, in both configurations, to a given source of voltage V. Then net energy stored in series combination `u_s = 1/2 C_s.V^2` and net energy stored in parallel combination `u_p = 1/2 C_p V^2 rArr u_s/u_p = C_s/C_p = (1 muF)/(9muF) =1/9`. |
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