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Newton's Laws of Motion and FrictionA bar of mass m, is placed on a plank of mass m, which rests on a smooth horizontal plane. The coefficient of frictionbetween the surfaces of bar and plank is k. The plank is subjected to a horizontal force F depending on time t as F - at,where a is a constant. The moment of time t, at which the plank starts sliding is :58.akgm +m2(m1 + m2)kg2)mim2ka(4) (m, + m2)3ka |
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Answer» i think 2nd option is correct plz inform me whether i am right or not yes u r right minimum force needed to overcome friction = k(m1+m2)g now that force = F = at => at = k(m1+m2)g=> t = k(m1+m2)g/a |
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