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`NH_(3)(g) + 3Cl_(2)(g) rarr NCl_(3)(g) + 3HCl(g), " "DeltaH_(1)` `N_(2)(g)+3H_(2)(g)rarr 2NH_(3)(g), " "DeltaH_(2)` `H_(2)(g)+ Cl_(2)(g) rarr 2HCl(g) , " " DeltaH_(3)` The heat of formation of `NCl_(3)` in the terms of `DeltaH_(1), DeltaH_(2) "and" DeltaH_(3)` isA. `DeltaH_(f)=-DeltaH_(1)+(DeltaH_(2))/(2)-(3)/(2) DeltaH_(3)`B. `DeltaH_(f)=DeltaH_(1)+(DeltaH_(2))/(2)-(3)/(2) DeltaH_(3)`C. `DeltaH_(f)=-DeltaH_(1)-(DeltaH_(2))/(2)-(3)/(2) DeltaH_(3)`D. None |
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Answer» Correct Answer - A `(1)/(2)N_(2)(g)+(3)/(2)Cl_(2)(g)rarr NCl_(3)(g)` `DeltaH=-DeltaH_(1)+(DeltaH_(2))/(2)-(3)/(2)DeltaH_(3)` |
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