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NH_(4)COONH_(2(s))hArr2NH_(3(g))+CO_(2(g)) if eqilibrium prassure is 3 atm for the above reaction K_(p) for the reaction is |
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Answer» <P>4 `thereforeP_(NH_(3))=2ATM, P_(CO_(2))=1` `K_(p)=[P_(NH_(3))]^(2).[P_(CO_(2))]=2^(2)xx1=4` |
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