1.

NH_(4)HS(s) hArr NH_(3)(g)+H_(2)S(g) In the above reaction, if the pressure at equilibrium and at 300K is 100atm then what will be equilibrium constant K_(p) ?

Answer»

`2500atm^(2)`
`50atm^(2)`
`100atm^(2)`
`200atm^(2)`

Solution :`NH_(4)HS(s)hArrNH_(3)(g)+H_(2)S(g)`
`{:(1,0,0,"INITIALLY"),(1-alpha,alpha,alpha,"at equlibrium"):}`
ACCORDING to question at the equlibrium
`alpha+alpha=100impliesalpha=50` atm.
`thereforeK_(P)=P_(NH_(3))xxP_(H_(2)S)=50xx50=2500atm^(2)`


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