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[Ni(CN)_(4)]^(2-) is diamagnetic , while [NiCl_(4)]^(2-) is paramagentic, explain using crystal field theory. |
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Answer» Solution :`(a) [Ni(CN)_(4)]^(2-)` `Ni=3d^(8)4S^(2)` `Ni^(2+)=3d^(8)`  Nature of the complex-Low spin (Spin PAIRED) Ligand filled electronic configuration of central metal ion, `t_(2g)^(6)e_(g)^(2)` Magnetic property : No unpaired electron (`CN^(-)` is strong filled ligand ), hence it is dimagnetic. Magnetic MOMENT : `mu_(s)=0` `(b)=[NiCl_(4)]^(2-)` `Ni=3d^(8)4S^(2)` `Ni^(2+)=3d^(8)`  Naute of the complex,-HIGH spin Ligand filled electronic configuration of central metal ion , `t_(2g)^(6)e_(g)^(2)` Magnetic property : Two unpaired electron (`Cl^(-)` is weak field ligand). Hence it is paramagnetic Magnetic moment : `mus=sqrt(2(2+2))` `=sqrt(8)=2.83BM` |
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