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[Ni(CN)_4 ]^(2-)is diamagnetic ,while[NiCl_4]^(2) -is paramagnetic ,explain using crystal field theory. |
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Answer» Solution :(a) `[Ni(CN)_(4)]^(2-)` `Ni=3d^(8)4S^(2)` `Ni^(2+)=3d^(8)`  Nature of the complex - Low spin (Spin paired) Ligand filled electronic configuration of central metal ion, `t_(2g)^(6)e_(g)^(2)` Magnetic PROPERTY : No unpaired ELECTRON (`CN^(-)` is strong filled ligand), HENCE it is diamagnetic. Magnetic moment : `mu_(s)=0` (b) `[NiCl_(4)]^(2-)` `Ni=3d^(8)4S^(2)` `Ni^(2+)=3d^(8)`  Nature of the complex, - high spin Ligand filled electronic configuration of central metal ion, `t_(2g)^(6)e_(g)^(2)` magnetic property : Two unpaired electron (`Cl^(-)` is weak field ligand). Hence it is paramagnetic Magnetic moment : `mu_(s)=sqrt(2(2+2))` `=sqrt(8)=2.83BM` |
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