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Nicker crystallizes in an fcc unit cell with a cell-edge length of 0.3524nm. Calcualte the radius of the nickel atom |
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Answer» 0.1624nm or `4r_(Ni)=asqrt(2)` `r_(Ni)=(asqrt(2))/(4)=sqrt(2)/(4)xx0.3524=0.1246` NM |
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