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| 1. |
[NiCl_(4)]^(2-) is paramagnetic while [Ni(CO)_(4)] is diamagnetic though both are tetrahedral. Why ? |
| Answer» Solution :In `[NiCl_(4)]^(2-)`, Ni is +2 oxidation STATE with the configuration `3d^(8)4s^(0)` . `CL^(-)` is weak ligand. It cannot pair up the electrons in 3d orbitals. Hence, it is paramagnetic. In `[Ni(CO)_(4)]`, Ni is in zero oxidation state with the configuration `3d^(8)4s^(2)`. In the presence of `CO` ligand, the 4s electrons shift to 3d to pair up 3d electrons. Thus, there is no unpaired electron PRESENT. Hence, it is DIAMAGNETIC. | |