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निम्न फलनों के मान ज्ञात कीजिये - `int(cos theta d theta)/(a+b sin theta)` |
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Answer» माना `I = int(cos theta d theta)/(a + b sin theta)` माना `a + b sin theta = t` `rArr " " bcos theta d theta = dt rArr cos theta = (1)/(b) dt` `therefore " "I = (1)/(b) int (dt)/(t) = (1)/(b) log t` ` therefore" "I = (1)/(b) log (a+b sin theta)` |
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