1.

निम्न व्यंजकों के गुणनखण्ड ज्ञात कीजिए।1. x2 + 7x + 122. x2 – 14x + 483. x2 – 7x – 18

Answer»

1. x2 + 7x + 12 = x2 + (3 + 4)x + 12 (12 = 3 × 4)

= x2 + 3x + 4x + 12 

= x(x + 3) + 4(x + 3) 

= (x + 3)(x + 4)

2. x2 – 14x + 48 

= x2 – (6 + 8)x + 48 (48 = 6 × 8)

= x2 – 6x – 8x + 48 

= x(x – 6) – 8(x – 6) 

= (x – 6)(x – 8)

3. x2– 7x – 18 

= x2 – (9 – 2)x – 18 

= x2 – 9x + 2x – 18 

= x(x – 9) + 2(x – 9) 

= (x – 9)(x + 2)



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