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निम्न व्यंजकों के गुणनखण्ड ज्ञात कीजिए(i) x3 – 8y3(ii) a3 – 0.216(iii) 16a4 + 54a(iv) a6 – 7a3 – 8 |
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Answer» (i) x3 – 8y3 = (x)3 – (2y)3 = (x – 2y)(x2 + 4y2 + 2xy) (ii) a3 – 0.216 = (a)3 – (0.6)3 = (a – 0.6)(a2 – 0.36 + 0.6 a) (iii) 16a4 + 54a = 2a(8a3 + 27) = 2a[(2a)3 + (3)3] = 2a[(2a + 3)(4a2 + 9 – 6a)] (iv) a6 – 7a3 – 8 = a – (8 – 1)a3 – 8 = a6 – 8a3 + a3 – 8 = a (a3 – 8) – 1(a3 – 8) = (a3 – 8)(a3 + 1) = [(a)3 – (2)3][(a)3 + (1)3] = (a – 2)(a2 + 4 + 2a)(a + 1)(a + 1 – a) |
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