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निम्नलिखित के मान ज्ञात कीजिए : `tan^(-1)(tan""(3pi)/(6))` |
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Answer» Correct Answer - `pi/6` Range of `tan^(-1)` is `(-pi/2,pi/2)` `therefore tan^(-1)(tan(7pi)/6)=tan^(-1){tan(pi+pi/6)}` `=tan^(-1){tanpi/6{=pi/6`. |
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