1.

निम्नलिखित के मान ज्ञात कीजिए : `tan^(-1)(tan""(3pi)/(6))`

Answer» Correct Answer - `pi/6`
Range of `tan^(-1)` is `(-pi/2,pi/2)`
`therefore tan^(-1)(tan(7pi)/6)=tan^(-1){tan(pi+pi/6)}`
`=tan^(-1){tanpi/6{=pi/6`.


Discussion

No Comment Found